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ECE :: Digital Electronics

Digital Electronics - Section 1
Digital Electronics - Section 2
Digital Electronics - Section 3
Digital Electronics - Section 4
Digital Electronics - Section 5
Digital Electronics - Section 6
Digital Electronics - Section 7
Digital Electronics - Section 8
Digital Electronics - Section 9
Digital Electronics - Section 10
Digital Electronics - Section 11
Digital Electronics - Section 12
Digital Electronics - Section 13
Digital Electronics - Section 14
Digital Electronics - Section 15
Digital Electronics - Section 16
Digital Electronics - Section 17
Digital Electronics - Section 18
Digital Electronics - Section 19
Digital Electronics - Section 20
Digital Electronics - Section 21
Digital Electronics - Section 22
Digital Electronics - Section 23
Digital Electronics - Section 24
Digital Electronics - section-25
Digital Electronics - Section-26

  1. Karnaugh map is used to

    2. A.
    minimise the number of flip flops in a digital circuit
    B.
    minimise the number of gates only in a digital circuit
    C.
    minimise the number of gates and fan in a digital circuit
    D.
    design gates

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  2. The main advantage of CMOS circuit is

    3. A.
    high gain
    B.
    high output impedance
    C.
    low power consumption
    D.
    high gain and high output impedance

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  3. Floating gate is fabricated for making MOS

    4. A.
    ROM
    B.
    PROM
    C.
    EPROM
    D.
    EAROM

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  4. A 12-bit binary counter has the following state. The octal number represented is

    5. A.
    677
    B.
    7163
    C.
    7128
    D.
    7183

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  5. (1111.11)2 is

    6. A.
    (1.01)10
    B.
    (0.75)10
    C.
    (15.3)10
    D.
    (15.75)10

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  6. The number of flip-flops required to build a mod-19 counter is

    7. A.
    4
    B.
    5
    C.
    6
    D.
    7

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  7. The number of flip-flops needed to divide the input frequency by 32 is

    8. A.
    2
    B.
    4
    C.
    5
    D.
    16

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  8. Given two numbers A and B in sign magnitude representation in an eight bit format A = 00011110 and B = 10011100 then A ⊕ B gives

    9. A.
    10000010
    B.
    00011111
    C.
    10011101
    D.
    11100001

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  9. The 8086 arithmetic instruction work on

    1. signed and unsigned numbers
    2. ASCII data
    3. unpacked BCD data
    Select the correct answer using the codes given below :

    10. A.
    1 and 2
    B.
    1 and 3
    C.
    2 and 3
    D.
    1, 2 and 3

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  10. For the K map of the given figure the simplified Boolean expression is

    11. A.
    A + BC
    B.
    A + BC
    C.
    A + B C
    D.
    A + B C

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