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Answer : Option A
Explanation :
We have log10 = 2
Or, we can write it as log10 = 2 log10 10
Or, log10 = 2 log10 100
Therefore, both side log will be canceled out.
Or, = 4
We know that √x = a, or x1/2 = a, then x = a2
Similarly, x2 - 12x + 36 = 42
Or, x2 - 12x + 36 = 16
Or, x2 - 12x + 20=0
Now, (x-2)(x-10) = 0
Or, x-2 = 0, and x-10 =0
Therefore, we can say that x = 2, x = 10
Answer : Option D
We know that, if a number is in the form
Then the output will be the number itself, i.e., the expressionis equals to 10.
Since, logm m = 1
Therefore, log10 (10) = 1
Answer : Option B
Let x = antilog (pa+qb+rc)z
Or, we can say that log x = pa+qb+rcz
Or, log x = p log10 x + q log10 y + r log10 z
We know that, p log q = log qp
Or, log x = log10 xp + log10 yq + log10 zr
Or, we know that log a + log b = log ab
Or, log x = log (xp yq zr)
Since, both sides log will be canceled out
Therefore, x = xp yq zr)
Hence, the antilogarithm of pa+qb+rc = x xp yq zr)
Answer : Option C
We have an expression logb a2 logc b2 loga c2 Now, we know that p log q = log qp
Similarly, (2 logb a) (2 logc b) (2 loga c) Now, [2*2*2]
Therefore, 8 * 1 = 8
= 2, find the value of x. 
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= 4
is 
