By T-Ds Equations at constant entropy CpdT=T∂V∂TPdP andCv=−T(∂P∂T)P(∂V∂T)S⇒CPCV=(∂P∂V)S(∂P∂V)T Since, CP is always greater than CV the ratio of isothermal compressibility and isentropic (reversible adiabatic) process is always greater than 1⇒ the difference is greater than zero.
If we see the P−V plots for isobaric, adiabatic and isothermal process the area under the graph is more in case of isobaric process hence the work done in isobaric process is maximum.
The joule Thomson coefficient is given as μi=(∂T∂P)H, And since for an ideal gas enthalpy is strictly only function of temperature which implies constant temperature and hence the joule thomson coefficient becomes zero. Physically both the contervining effects of throttling are balancing each other.
The molar excess Gibbs free energy, gE, for a binary liquid mixture at T and P is given by, (gE/RT) = A . x₁. x₂, where A is a constant. The corresponding equation for ln y₁, where y₁ is the activity co-efficient of component 1, is
Since activity co-efficient is defined as γi=Fugacity in real solutionFugacity in ideal solution,lnγ1=¯nGElRT=0(for ideal solution), Since there will be no excess gibbs free energy for ideal solution. So, in the question it will be better if replace ideal gas by ideal solution.
Entropy is the measure of randomness or disorderness in the system by third law it s given that at absolute zero temperature the entropy is zero, for a perfect crystal.
The inversion curve is drawn by joining all the inversion points (which are nothing but maximum points for particular conditions) as the slope (joule thomson coefficient) is zero for a maximum the joule Thomson coefficient is zero.
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