Discussion :: Logarithm
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If logx\([\frac { 9 } {16 } ]=\)\(-[\frac { 1 } {2 } ],\)then x is equal to:
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A.
\(-\frac { 3} {4 } \) |
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B.
\(\frac { 3} {4 } \) |
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C.
\( \frac {8 1 } { 256 }\) |
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D.
\( \frac {256 } { 81}\) |
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Answer : Option D
Explanation :
If logx\([\frac { 9 } {16 } ]=\)\(-[\frac { 1 } {2 } ]\)
\(\frac { X^-1/2 } { } \)=\(\frac {9 } {16} \)
\(\frac { 1 } { \sqrt{X}}\)=\(\frac {9 } {16} \)
\( { \sqrt{X}
} { } \)=\(\frac {16 } {9} \)
x =[\(\frac {16 } {9} \)]2
x =\( \frac {256 } { 81}\)
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