Logarithm - Arithmetic Aptitude Questions and Answers

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If log_{x $[\frac { 9 } {16 } ]=$ $-[\frac { 1 } {2 } ],$}then x is equal to:

$-\frac { 3} {4 }$

$\frac { 3} {4 }$

$\frac {8 1 } { 256 }$

$\frac {256 } { 81}$

Answer : Option D

Explanation :

If log_{x_{$[\frac { 9 } {16 } ]=$}_{$-[\frac { 1 } {2 } ]$}}

$\frac { X^-1/2 } { }$ = $\frac {9 } {16}$

$\frac { 1 } { \sqrt{X}}$ = $\frac {9 } {16}$

${ \sqrt{X} } { }$ = $\frac {16 } {9}$

x =[ $\frac {16 } {9}$ ]²

x = $\frac {256 } { 81}$

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