Logarithm - Arithmetic Aptitude Questions and Answers

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If log\( \frac {a} {b } \)+log\( \frac {b} {a } \)=log (a + b), then

a + b = 1

a - b = 1

a = b

a² - b² = 1

Answer : Option A

Explanation :

log\( \frac {a} {b } \)+log\( \frac {b} {a } \)=log (a + b)

log (a + b) = log[\( \frac {a} {b } \times\)\( \frac {b} {a } \)]=log1

So, a + b = 1.

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