Discussion :: Thermodynamics
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The efficiency of the Carnot cycle is (where T1 and T2 = Highest and lowest temperature during the cycle)
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A.
\(\frac { T_1 } { T_2 } - 1\) |
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B.
\(1 - \frac { T_1 } { T_2 }\) |
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C.
\(1 - \frac { T_2 } { T_1 } \) |
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D.
\(1 + \frac { T_2 } { T_1 } \) |
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Answer : Option C
Explanation :
No answer description available for this question.
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