Hydraulics and Fluid Mechanics - Mechanical Engineering Questions and Answers

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The torque required to overcome viscous resistance of a collar bearing is (where R₁ and R₂ = External and internal radius of collar)

$\frac { \mu n^2 N } { 60 t } (R_1 - R_2)$

$\frac { \mu n^2 N } { 60 t } (R_1^2 - R_2^2)$

$\frac { \mu n^2 N } { 60 t } (R_1^3 - R_2^3)$

$\frac { \mu n^2 N } { 60 t } (R_1^4 - R_2^4)$

Answer : Option D

Explanation :

No answer description available for this question.

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