Discussion :: Hydraulics and Fluid Mechanics
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A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be
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A.
\(\frac { 2 A\sqrt{H_1} } { C_d \times a\sqrt{2g} }\) |
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B.
\(\frac { 2 A\sqrt{H_2} } { C_d \times a\sqrt{2g} }\) |
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C.
\(\frac { 2 A(\sqrt{H_1} - \sqrt{H_2})} { C_d \times a\sqrt{2g} }\) |
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D.
\(\frac { 2 A({H_1^\frac{3}{2}} - {H_2^\frac{3}{2}})} { C_d \times a\sqrt{2g} }\) |
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Answer : Option C
Explanation :
No answer description available for this question.
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