Hydraulics and Fluid Mechanics - Mechanical Engineering Questions and Answers

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Discussion :: Hydraulics and Fluid Mechanics

A compound pipe of diameter d₁, d₂ and d₃ having lengths l₁, l₂ and l₃ is to be replaced by an equivalent pipe of uniform diameter d and of the same length (l) as that of the compound pipe. The size of the equivalent pipe is given by

$\frac { l } { d^2 } = \frac { l_1 } { d_1^2 } + \frac { l_2 } { d_2^2} + \frac { l_3 } { d_3^2}$

$\frac { l } { d^3 } = \frac { l_1 } { d_1^3 } + \frac { l_2 } { d_2^3} + \frac { l_3 } { d_3^3}$

$\frac { l } { d^4 } = \frac { l_1 } { d_1^4} + \frac { l_2 } { d_2^4} + \frac { l_3 } { d_3^4}$

$\frac { l } { d^5 } = \frac { l_1 } { d_1^5 } + \frac { l_2 } { d_2^5} + \frac { l_3 } { d_3^5}$

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Answer : Option D

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