Engineering Mechanics - Mechanical Engineering Questions and Answers

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The maximum height of a projectile on a horizontal plane, is

$\frac { u^2 sin^2\alpha } { 2g }$

$\frac { u^2 cos^2\alpha } { 2g }$

$\frac { u^2 sin^2\alpha } { g }$

$\frac { u^2 cos^2\alpha } { g }$

Answer : Option A

Explanation :

No answer description available for this question.

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