Discussion :: Engineering Mechanics
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The centre of gravity of a trapezium with parallel sides a and b lies at a distance of y from the base b, as shown in the below figure. The value of y is
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A.
\(h(\frac { 2a + b } { a + b })\) |
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B.
\( \frac{h} {2}(\frac { 2a + b } { a + b })\) |
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C.
\( \frac{h} {3}(\frac { 2a + b } { a + b })\) |
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D.
\( \frac{h} {3} (\frac { a + b } { 2a + b })\) |
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Answer : Option C
Explanation :
No answer description available for this question.
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