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The equivalent length of a simple pendulum which gives the same frequency as compound pendulum is

$\frac { h } { kG^{2} + h^{2} }$

$\frac { kG^{2} + h^{2} } { h }$

$\frac{ h^{2} } { kG^{2} + h^{2} }$

$\frac{ kG^{2} + h^{2} } { h^{2} }$

Answer : Option B

Explanation :

No answer description available for this question.

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