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The time of flight (t) of a projectile on an upward inclined plane is(where u = Velocity of projection, Î± = Angle of projection, and Î² = Inclination of the plane with the horizontal.)

t = $\frac {g cos\beta} { 2u sin(\alpha - \beta) }$

t = $\frac {2u sin(\alpha - \beta)} { g cos\beta }$

t = $\frac {g cos\beta} { 2u sin(\alpha + \beta) }$

t = $\frac {2u sin(\alpha + \beta)} { g cos\beta }$

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Answer : Option B

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