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  1. What will be the output of the program? 

    int i = (int) Math.random();

    2. A.
    i = 0
    B.
    i = 1
    C.
    value of i is undetermined
    D.
    Statement causes a compile error

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    Answer : Option A

    Explanation :

    Math.random() returns a double value greater than or equal to 0 and less than 1. Its value is stored to an int but as this is a narrowing conversion, a cast is needed to tell the compiler that you are aware that there may be a loss of precision.

    The value after the decimal point is lost when you cast a double to int and you are left with 0.

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