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Discussion :: Flow Control

  1. What will be the output of the program?

    int I = 0; 
label:  
        if (I 2) {   
        System.out.print("I is " + I);   
        I++;  
        continue label; 
}

    2. A.

    I is 0
    B.

    I is 0 I is 1
    C.

    Compilation fails.
    D.

    None of the above

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    Answer : Option C

    Explanation :

    The code will not compile because a continue statement can only occur in a looping construct. If this syntax were legal, the combination of the continue and the if statements would create a kludgey kind of loop, but the compiler will force you to write cleaner code than this.

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