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Discussion :: Testing New

  1. Determine Output:

    #define int char
    void main()
    {
          int i = 65;
          printf("sizeof(i)=%d", sizeof(i));
    }
    2. A.

     sizeof(i)=2
    B.

     sizeof(i)=1
    C.

     Compiler Error
    D.

     None of These

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    Workspace

    View Answer

    Answer : Option B

    Explanation :

    Since the #define replaces the string int by the macro char.

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