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  1. A copper wire of radius r and length l has a resistance of R. A second copper wire with radius 2r and length l is taken and the two wires are joined in a parallel combination. The resultant resistance of the parallel combination of the two wires will be

  2. A.

     5 R

    B.

     5 R/4

    C.

     4 R/5

    D.

     R/5

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    Answer : Option D

    Explanation :

    1st copper wire: R = pl/A = pl/ πr2
    2ndcopper wire: R’ = p’l’/A’ = pl/(4 πr2) = R/4
    If joined in parallel, (1/Req) = (1/R) + (1/R’)
    = 1/R + 4/R
    = 5/R
    Req = R/5


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