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  1. The mass of P4O10 that will be obtained from the reaction of 1.33 gram of P4 and 5.07 of oxygen is

    2. A.

     2.05 gram
    B.

     3.05 gram
    C.

     4.05 gram
    D.

     5.05 gram

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    Answer : Option B

    Explanation :

    Balanced chemical equation:
    P4 + 5O2 --------> P4O10
    1 mol 5 mol 1 mol
    124g 160g 284g
    Here limiting reagent is P4.
    So, 124g of P4 produce P4O10 = 284g
    Therefore,
    1.33g of P4 produce P4O10 = (284/124)*1.33
    = 3.05g

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