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Discussion :: Network Analysis and Synthesis

  1. In following circuit, steady state is reached with S open, S is closed at t = 0, the current I at t = 0+ is given by

  2. A.
    9 Ω
    B.
    6 Ω
    C.
    7 Ω
    D.
    10 Ω

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    Answer : Option C

    Explanation :

    When steady state is reached with s open, capacitor will act as open circuit

    Current in 4Ω resistor will be = 6A at steady state.

    Voltage across 4Ω = 6 x 4 24 volt.

    Current in 2Ω resistor due to 6A 3A current due to 16 V, source.

    I = 16/2 8A, this current divide in (2 + 2) Ω is 4Ω resistor current in 2Ω resistor 4A + 3A 7A.


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