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Discussion :: Network Analysis and Synthesis

  1. A current 10 sin (200t) A flows through a 5 mH inductance. The expression for voltage is

    2. A.
    10 sin (200t + 90°)
    B.
    10 sin (200t - 90°)
    C.
    10 sin(1000t + 90°)
    D.
    10 sin (1000t - 90°)

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    Answer : Option D

    Explanation :

    Z = jXL = jωL = = 1∠90° and V = IXL

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