Network Analysis and Synthesis - ECE Questions and Answers

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An RL series circuit is initially relaxed. A step voltage E is applied. If t is time constant, voltage across R and L will be equal at t =

t ln 2

Answer : Option B

Explanation :

v_R = E(1 - e^-t/t) and v_L = E e^-t/t or 1 - e^-t/t = e^-t/t. This happens at t = t in 2.

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