Discussion :: Network Analysis and Synthesis
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In the circuit shown, the steady state is reached with S open S is closed at t = 0, the current I in the 1 Ω resistor connected is to be determined at t = 0+ is given by
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Answer : Option A
Explanation :
If steady is reached L will be short circuited the current in 1 Ω resistor I = 4/2 
2A.
It will act as current source in parallel with inductor.
Now apply superposition theorem consider 4 volt source, current source will be open and inductor also open.
Current in R' = 1 Ω resistor = 2A.
When current source consider, voltage source will be short circuited and current due to inductor is 1A in opposite direction.
Total current 2 - 1 = 1 A.
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