Network Analysis and Synthesis - ECE Questions and Answers

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In figure, the voltage V₁ = 4∠0 V. The source voltage V₂ is

8 - j8 volts

4 - j4 volts

8 - j4 volts

8 - j16 volts

Answer : Option C

Explanation :

I_R = 2∠OA, I₁ = 2∠-90° = -j 2A.

Total current = 2 - j2.

V₂ = 2 (2 - j2) + 4∠0 = 8 - j4 volts.

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