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  1. Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is whit with power spectral density SN(f) = N0/2 = 10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1 MHz. Let Yk represent the random variable y(tk).
    Yk = nNk if transmitted bit bk = 0
    Yk = a + Nk if transmitted bit bk = 1
    Where Nk represents the noise sample value. The noise sample has a probability density function, PNk(n) = 0.5ae-a|n| (This has mean zero and variance 2/a2). Assume transmitted bits to be equiprobable and threshold z is set to a/2 = 10-6 V.

    The probability of bit error is

    2. A.
    0.5 x e-3.5
    B.
    0.5 x e-5
    C.
    0.5 x e-7
    D.
    0.5 x e-10

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    Answer : Option D

    Explanation :

    Probability of error

    = 0.5e-107 x 10 -6 = 0.5e-10.

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