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  1. An FM transmitter delivers 80W to a load of 30 W when no modulation is present. The carrier is now frequency modulated by a single sinusoidal signal and the peak frequency deviation is so adjusted to make the amplitude of the second sideband is zero in the given output.
    J0(0, 0) = 1,
    J0(2, 4) = 0,
    J0(3.8) = - 0.4,
    J0(5.1)= - 0.1
    J1(2, 4) = 0.52,
    J1((3.8) = 0,
    J1(5.1) = - 0.33,
    J2(2.4) = 0.1
    J2(3.8)= 0.41,
    J2(5.1) = 0
    The power in all the remaining sidebands is :

    2. A.
    84 W
    B.
    97.44 W
    C.
    100 W
    D.
    77.44 W

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    Answer : Option D

    Explanation :

    Total power of the FM transmitter = 80 W to a load of 50 W

    second side band amplitude = J2(β) = 0

    ∴ β = 5.1

    Average Power = (J0(β))2 x 100 = (0.16)2 x 100 = 2.56 W

    Power in all remaining = 80 - 2.56 = 77.44 .

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