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  1. Find the maximum power that can be delivered to a load

  2. A.
    0.025 W
    B.
    2.5 W
    C.
    2.5 W
    D.
    0.25 W

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    Answer : Option D

    Explanation :

    PL = I2R = x R •••(i)

    where zS = 100 + j50

    zL = 100 - j50

    Putting the values in eq. (i)

    PL =X l00 = 0.25 watts.


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