Discussion :: Exam Questions Paper
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The analog signal given below is sampled at 1200 samples per second. m(t) = 2 sin 120 pt + 3 sin 240 pt + 4 sin 360 pt + 5 sin 480 pt + 6 sin 600 pt + 7 sin 720 pt. The folding (maximum) frequency is __________ .
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Answer : Option C
Explanation :
Folding frequency (max.) =
= 600 Hz.
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