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Discussion :: Digital Electronics

  1. The Boolean expression for the circuit of the given figure

    2. A.
    A {F + (B + C) (D + E)}
    B.
    A [F + (B + C) (DE)]
    C.
    A + F + (B + C) (D + E)]
    D.
    A [F + (BC) (DE)]

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    Answer : Option A

    Explanation :

    B and C in parallel give B + C. Similarly D and E in parallel give D + E. (B + C) in series with (D + E) give (B + C) (D + E). Since F is in parallel we get F + (B + C) (D + E). Finally A is in series. Therefore we get A[F + (B + C) (D + E)].

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