Discussion :: Communication Systems
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A carrier is phase modulated (PM) with frequency deviation of 10 kHz by a single tone frequency of 1 kHz. If the single tone frequency is increased to 2 kHz, assuming that phase deviation remains unchanged, the bandwidth of the PM signal is
Answer : Option D
Explanation :
Frequency deviation = 10 kHz, fm = 1 kHz
2(fm + Df)
Bandwidth = 22 kHz
2(10 + 1) 22 kHz
fm is doubled
Hence 22 x 2 44 kHz bandwidth.
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