Discussion :: Analog Electronics
-
In the following figure C = 0.02 μF, and Vth is known to be of frequency ω = 107 rad/sec and rd = 2.5 Ω and ZTh = RTh = 10 Ω Then phase angle between id and Vd

Answer : Option A
Explanation :

Zd = (rd)11 (-jxd)
2 - JΩ
θ = tan-1 (-1/2)
26.56 .
Be The First To Comment

Whatsapp
Facebook