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Discussion :: Analog Electronics

  1. Leakage current approximately doubles for every 10°C increase in the temperature of a transistor has ICBO = 400 nA at 25°C, then its leakage current at 80°C

    2. A.
    10 μA
    B.
    18 μA
    C.
    20 μA
    D.
    15 μA

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    Answer : Option B

    Explanation :

    ICBO = (400 x 10-9) 2(80-25)/10 = 18 μA.

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