Discussion :: PHP - CS
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What will be the output of the following PHP code ?
<?php
$x = 4;
$y = 3;
function fun($x = 3, $y = 4)
{
$z = $x+$y/$y+$x;
echo "$z";
}
echo $x;
echo $y;
echo $z;
fun($x, $y);
?>
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Answer : Option D
Explanation :
Firstly, the statements outside the function are printed, since z is not defined it’ll no value is printed for z. Next the function is called and the value of z inside the function is printed.
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