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Discussion :: PHP - CS

  1. What will be the output of the following PHP code ?

    <?php
    $x = 5;
    function fun()
    {
        echo "$x";
    }
    fun();
    ?>
    2. A.

     0
    B.

     5
    C.

     Nothing
    D.

     Error

    View Answer

    Workspace

    View Answer

    Answer : Option C

    Explanation :

    The variable x is not defined inside the function fun(), therefore nothing is printed on the screen.

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