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What is the output of the code shown below?

A = [[1, 2, 3],

[4, 5, 6],

[7, 8, 9]]

[A[i][len(A)-1-i] for i in range(len(A))]

[1, 5, 9]

[4, 5, 6]

[3, 5, 7]

[2, 5, 8]

Answer : Option C

Explanation :

This expression scales the common index to fetch A[0][2], A[1][1], etc. We assume the matrix has the same number of rows and columns.

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