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  1. What will be the output of given code snippet?

     class program
     {
         public static void Main(string[] args)
         {
             try
             {
                 throw new NullReferenceException("C");
                 Console.WriteLine("A");
             }
             catch (ArithmeticException e) 
             {
                 Console.WriteLine("B");
             }
             Console.ReadLine();
         }
     }
    2. A.
    A
    B.
    B
    C.
    Compile time error
    D.
    Runtime error

    View Answer

    Workspace

    View Answer

    Answer : Option D

    Explanation :

    try block is throwing NullPointerException but the catch block is used to counter Arithmetic Exception. Hence NullPointerException occurs since no catch is there which can handle it, runtime error occurs.

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