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  1. What is the output of this program?

    #include < iostream >

    using namespace std;

    int main()

    {

    char arr[20];

    int i;

    for(i = 0; i < 10; i++)

    *(arr + i) = 65 + i;

    *(arr + i) = '\0';

    cout << arr;

    return(0);

    }

  2. A.
    ABCDEFGHIJ
    B.
    AAAAAAAAAA
    C.
    JJJJJJJJ
    D.
    none of the mentioned

    View Answer

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    Answer : Option A

    Explanation :

    Each time we are assigning 65 + i. In first iteration i = 0 and 65 is assigned. So it will print from A to J.


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