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  1. Maximum data rate of a channel for a noiseless 3-kHz binary channel is

  2. A.

     3000bps

    B.

     6000 bps

    C.

     1500 bps

    D.

     None of these

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    Answer : Option B

    Explanation :

    Maximum data rate = 2Hlog2V bps, where H is the bandwidth, V is the discrete levels. Here H is 3 kHz and V is 2.
    So, data rate = 2*3000 log22 bps = 6000 bps.


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