Discussion :: Waste Water Engineering
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For having central angle α, the area of cross-section of sewers running partially full, is
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A.
A = \( \frac { D^2} { 2 } \) [\(\frac { nα } { 180^0 } \) -- \(\frac { sin α } { 2 } ]\) |
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B.
A = \( \frac { D^2} { 4 } \)[ \(\frac { nα } { 360^0 } \) - \(\frac { sin α } { 2 } ]\) |
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C.
A = \( \frac { D^2} { 4 } \) [ \(\frac { nα } { 360^0 } \) - \(\frac { cos α } { 2 } ]\) |
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D.
A =\( \frac { D^2} { 2 } \) [ \(\frac { nα } { 360^0 } \) - \(\frac { cos α } { 2 } ]\) |
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Answer : Option B
Explanation :
No answer description available for this question.
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