Discussion :: Waste Water Engineering
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For a circular sewer of diameter D running partially full with central angle α,
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A.
\( \frac { d} { D } \) = \(\frac { 1 } { 2 } \) [ 1- cos \(\frac { α } { 2 } \) ] |
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B.
\(\frac { a} { A } \) = [ \(\frac { n} { 360^0 } \) - \(\frac { sina } { 2n } \)] |
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C.
\(\frac { D } { P } \) = [ \(\frac { α} { 360^0 } \) |
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D.
\(\frac { r } { R }\) = [ 1-\( \frac { 360^0 sinα} { 2nα } \) ] |
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E.
all the above. |
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Answer : Option E
Explanation :
No answer description available for this question.
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