Correction per chain length of 100 links along a slope of 뱡 is
\(\frac { 1.5a^2 } { 100 }\)
\(\frac { 1.5a } { 100 }\)
\(\frac { 1.5a^3 } { 100 }\)
\( { 1 .5a^3} { } \)
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Answer : Option A
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