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  1. Fundamental momentum equation for a hydraulic jump, is

    2. A.

     D₁² - D₂² = (2q/g) × (V₁ - V₂)
    B.

     D₂² - D₁² = (2q/g) × (V - V₂)
    C.

     D₁² - D₂² = (2q/g) × (V₂ - V₁)
    D.

     D₁² + D₂² = (2q/g) × (V₂ - V₁)

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    Answer : Option B

    Explanation :

    Explanation Not Provided

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