Applied Mechanics - Civil Engineering Questions and Answers

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The centre of gravity of the trapezium as shown in below figure from the side is at a distance of

$\frac { h } { 3 }$ x $[\frac { b+2a} { b+a } ]$

$\frac { h } { 3 }$ x $[\frac { 2b+a} { b+a } ]$

$\frac { h } { 2 }$ x $[\frac { b+2a} { b+2a } ]$

$\frac { h } { 2 }$ x $[\frac { 2b+a} { b+a } ]$

Answer : Option A

Explanation :

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