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For the given values of initial velocity of projection and angle of inclination of the plane, the maximum range for a projectile projected upwards will be obtained, if the angle of projection is

a = $\frac { n } { 4 }$ - $\frac { \beta } { 2 }$

a = $\frac { n } { 2 }$ + $\frac { \beta } { 2 }$

a = $\frac { \beta } { 2 }$ - $\frac { n } { 2 }$

a = $\frac { n } { 4 }$ - $\frac { \beta } { 4}$

a = $\frac { n } { 2 }$ - $\frac { \beta } { 2 }$

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Answer : Option B

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