Discussion :: Applied Mechanics
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For the given values of initial velocity of projection and angle of inclination of the plane, the maximum range for a projectile projected upwards will be obtained, if the angle of projection is
A.
a = \(\frac { n } { 4 } \)- \(\frac { \beta } { 2 } \) |
B.
a = \(\frac { n } { 2 } \) +\(\frac { \beta } { 2 } \) |
C.
a = \(\frac { \beta } { 2 } \) - \(\frac { n } { 2 } \) |
D.
a = \(\frac { n } { 4 } \)- \(\frac { \beta } { 4} \) |
E.
a = \(\frac { n } { 2 } \)- \(\frac { \beta } { 2 } \) |
Answer : Option B
Explanation :
No answer description available for this question
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