Discussion :: Applied Mechanics
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A square hole is made in a circular lamina, the diagonal of the square is equal to the radius of the circleas shown in below figure the shift in the centre of gravity is
A.
\( \frac { r(n-0,75) } {( n-0.5) } \) |
B.
\( \frac { r(n-0,25) } {( n-0.75) } \) |
C.
\( \frac { r(n-0,5) } {( n-0.75) } \) |
D.
\( \frac { r(n-0,5) } {( n-0.25) } \) |
Answer : Option A
Explanation :
No answer description available for this question
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