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  1. The spherical ball of lead 3 cm in diameter is melted and recast into 3 spherical balls. The diameters of two of these are 1 ½ cm and 2 cm respectively. The diameter of third ball is?
    2. A.
    2.66 cm
    B.
    2.5 cm
    C.
    3 cm
    D.
    3.5 cm

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    Answer : Option B

    Explanation :

    4/3 π * 3 * 3 * 3 = 4/3 π[(3/2)3 + 23 + r3]

    r = 1.25

    d = 2.5

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