Discussion :: Time and Work
- A and B individually can finish a job in 20 and 30 days respectively. They start working together, and B leaves the job 5 days before completion, now the work will be finished in how many days?
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Answer : Option B
Explanation :
Note: Assume the total work = LCM of the given days
Take the LCM of days = LCM of (20 and 30) = 60
Let the total work = 60
A's one day work = 60/20 = 3 unit
B's one day work = 60/30= 2 unit
If (A+B) work, then they can finish the work in 60/5 = 12 days.
But ATQ, B left the job 5 days before
Assume that B has not left the work than B's 5-day work also included in the total work.
i.e., B's 5 day work = 5 * 2 = 10 units
Now, the total work = 60+10 = 70units
If (A+B)'s one day efficiency = 5
So, to complete the work it requires = 70/5 = 14 days.
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