Discussion :: Time and Work
- A does half as much as work as B in 1/6 of the time taken by B. Together they can complete the work in 10 days. B alone can complete the work in how many days?
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Answer : Option C
Explanation :
Let B does 1 work in x days
Then, A does [1/2] work in x/6 days
To do 1 unit work, A will take x/3 days
That means time ratio of A: B = x: x/3
Or time ratio = 1: 1/3
Or time ratio = 3: 1
As we know that the efficiency ratio is inversely proportional to time ratio
i.e., Efficiency ratio of A: B = 1: 3
ATQ,
(A+B) = 10 days
Total work = days* efficiency of (A+B)
Or, total work = 10 * 4 = 40 units
i.e., B can finish the work in = total work/ efficiency of B
So, B can finish the work in 40/1 = 40 days.
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