Discussion :: Time and Work
- A can finish a work in 10 days and B can finish the same work in 15 days. If they work alternatively, find the time taken to finish the job.
Answer : Option C
Explanation :
Note: Assume the total work = LCM of the given days
Take the LCM of days = LCM of (10 and 15) = 30
Let the total work = 30
Note: One day work = (total work/ days)
Now,
A's one day work = 30/10 = 3 unit
B's one day work = 30/15 = 2 unit
That means A and B works 5 unit works in 2 days
i.e., 2 days = 5 unit work
To complete the 30 work, multiply both sides with 6.
i.e., 2 days * 6 = 5 unit work * 6
Or, 12 days = 30 works
So, A and B require 12 days to finish the work.
Be The First To Comment