Discussion :: Time and Work
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A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
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Answer : Option C
Explanation :
| B's 10 day's work = |  | 1 | x 10 |  | = | 2 | . |
| 15 | 3 |
| Remaining work = | | 1 - | 2 | | = | 1 | . |
| 3 | 3 |
| Now, | 1 | work is done by A in 1 day. |
| 18 |
 | 1 | work is done by A in | | 18 x | 1 | | = 6 days. |
| 3 | 3 |
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