Discussion :: Time and Work
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A and B can do a piece of work in 30 days, while B and C can do the same work in 24 days and C and A in 20 days. They all work together for 10 days when B and C leave. How many days more will A take to finish the work?
Answer : Option A
Explanation :
| 2(A + B + C)'s 1 day's work = | ![]() | 1 | + | 1 | + | 1 | ![]() | = | 15 | = | 1 | . |
| 30 | 24 | 20 | 120 | 8 |
| Therefore, (A + B + C)'s 1 day's work = | 1 | = | 1 | . |
| 2 x 8 | 16 |
| Work done by A, B, C in 10 days = | 10 | = | 5 | . |
| 16 | 8 |
| Remaining work = | ![]() | 1 - | 5 | ![]() | = | 3 | . |
| 8 | 8 |
| A's 1 day's work = | ![]() | 1 | - | 1 | ![]() | = | 1 | . |
| 16 | 24 | 48 |
| Now, | 1 | work is done by A in 1 day. |
| 48 |
| So, | 3 | work will be done by A in | ![]() | 48 x | 3 | ![]() | = 18 days. |
| 8 | 8 |
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